Consider a mixture 'X' which is made by dissolving 0.4 mol of [Co(NH3)5SO4] Br and 0.4 mol of [Co(NH3)5Br]SO4 in water to make 4 L of solution. When 2 L of mixture 'X' is allowed to react with excess

Question

Consider a mixture 'X' which is made by dissolving 0.4 mol of [Co(NH3)5SO4] Br and 0.4 mol of [Co(NH3)5Br]SO4 in water to make 4 L of solution. When 2 L of mixture 'X' is allowed to react with excess of AgNO3, it forms precipitate 'Y'. The rest 2 L of mixture 'X' reacts with excess BaCl2 to form precipitate 'Z'. Which of the following statements is CORRECT.

(A) 0.2 mol of 'Z' is formed
(B) 'Y' is BaSO4 and 'Z' is AgBr
(C) 0.4 mol of 'Z' is formed
(D) 0.1 mol of 'Y' is formed

Prashant Kotian · Accepted Answer

Correct answer: A. 0.4 mol [Co(NH3)5SO4]Br + 0.4 mol [Co(NH3)5 Br] SO4 are present in 4 lit. solution. 2 lit. of mixture will contain 0.2 mol of each complex. 2 lit. mixture on reaction with excess AgNO3, 0.2 mole AgBr will be formed (Y). 2 lit. mixture on reaction with excess BaCl2, 0.2 mole BaSO4 will be formed (Z). ALLEN 

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