See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

2 2 AB A 2B     t = 0 a 0 0 t = t a - a a 2 a nT = a - a + a + 2 a = a(1 + 2a) So, i = 1 + 2 Now Tb = i  m  Kb Tb =(1 + 2)  m  Kb  = 0.1, m = 10, Kb = 0.5 Tb = 1.2  10  0.5 = 6 So boiling point = 106