The enthalpy of combustion of methane is -890 kJ. The volume of methane at 0°C and 1 atm to be burnt — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

Moles of methane required: n = 2670 kJ / 890 kJ/mol = 3.0 mol. At STP (0°C and 1 atm), the volume of 1 mole of any ideal gas is 22.4 L. Thus, the volume of 3 moles of methane is: V = 3.0 * 22.4 L = 67.2 L.