See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Let f(x) = ax3 + bx and tangent at   3 ,a b   intersect at   3 , a b  , then   2 2 2 3a b a b        2 0, 2        3 2 3 1 2 A ax bx 3a b x 2a dx          = k4   3 2 3 2 2 A ax 3a x 2a dx         = k4 = 16k4.