CH –CN A B C A, B & C respectively may be :- (A) CH –COOH, CH –NH and CH –NC (B) CH –CO–NH , CH –NH — NEET Chemistry Past Papers Chemistry Question

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CH –CN A B C A, B & C respectively may be :- (A) CH –COOH, CH –NH and CH –NC (B) CH –CO–NH , CH –NH and CH –CN (C) CH –CO–NH , CH –NH and CH –NC (D) CH–CH –NH , CH –NH and CH –NC 3 H2O/OH − −−−−−−−−−−−→ Partial hydrolysis Br2+KOH −−−−−−→ CHCl3+KOH −−−−−−−−−→ Δ 3 3 2 3 3 2 3 2 3 3 2 3 2 3 2 2 3 2 3 CH –CN A B C 3 Br2+KOH −−−−−−→ CHCl3+KOH −−−−−−−−−→ Δ 3 3 2 3 3 2 3 2 3 3 2 3 2 3 2 2 3 2 3 Assertion (A) :- Benzaldehyde is more reactive than propanal for NAR. (Nucleophilic addition reaction) Reason (R) :- The carbon atom of carbonyl group of benzaldehyde is less electrophillic than carbon atom of carbonyl group present in propanal. (1) Both (A) and (R) are correct but (R) is not correct explanation of (A). (2) (A) is correct but (R) is not correct. (3) (A) is not correct but (R) is correct. (4) Both (A) and (R) are correct and (R) is the correct explanation of (A). Which statement is NOT correct for benzene sulphonyl chloride? (1) It is known as Hinsberg's reagent. (2) It is used to distinguish, primary and secondary amines (3) On treatment with secondary amine it leads to a product, that is soluble in alkali. (4) It doesn't react with tertiary amine. Which of the following ligand can not act as flexidentate ligand. (1) (2) Isothiocyanate (3) EDTA (4) Carbonate SO−2 4 (1) (3) EDTA SO−2 4 The Hybridisation of central atom in Diborane, diamond and graphite are respectively. (1) sp , sp , sp (2) sp , sp , sp (3) sp , sp , sp (4) sp, sp , sp 2 3 2 3 3 2 3 3 3 2 3 (1) sp , sp , sp (2) sp , sp , sp (3) sp , sp , sp (4) sp, sp , sp 2 3 2 3 3 2 3 3 3 2 3 1001OMD303029230152 PHASE - MOCK TEST-2