For a certain reaction at 300K, K = 10, then G° for the same reaction is –_______×10–1 kJ mol–1. (Gi — JEE Mains Chemistry Past Papers Chemistry Question
Question
For a certain reaction at 300K, K = 10, then G° for the same reaction is –_______×10–1 kJ mol–1. (Given R = 8.314 JK–1 mol–1)
Answer: .
💡 Solution & Explanation
G° = –RT n K = –8.314 × 300 n (10) = 5744.14 J/mole = 57.44 × 10–1 kJ/mole
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