Aqueous solutions of 0.004 M - and 0.01 M - Glucose are isotonic. The percentage dissociation of is — Solutions and Colligative Properties Chemistry Question

💡 Solution & Explanation

Since isotonic: i_Na2SO4 * 0.004 = 1 * 0.01 => i = 2.5. Using i = 1 + (3-1)α => 2.5 = 1 + 2α => α = 0.75. Percentage dissociation = 75%.