See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

For instantaneous values Let 0 I I sin( t )   R 0 V IR I Rsin( t )     0I sin( t ) 2  0 E sin( t ) 2 z  0 R 2z cos z E    L x 3   L R V V E 7     E 7V  0 E E sin( t)   7 7sin( t)   sin t 1  t 2  