Number of P—H, P—O—P, P—O—H and P—O bonds in sodium dihydrogen pyrophosphate respectively are : — Chemical Bonding Chemistry Question

💡 Solution & Explanation

Step 1: Write down the formula for sodium dihydrogen pyrophosphate: Na2H2P2O7. The pyrophosphate skeleton features a P-O-P bridge: [O3P-O-PO3]^4-. Step 2: In the dihydrogen form (H2P2O7^2-), one acidic hydrogen is attached to each phosphorus atom via an oxygen atom (P-O-H), meaning there are exactly two P-O-H bonds and zero direct P-H bonds. Step 3: Each phosphorus atom is also double-bonded to a terminal oxygen atom (two P=O bonds on each P, giving 4 total P=O bonds). Therefore, the number of P-H, P-O-P, P-O-H, and P=O bonds are 0, 1, 2, and 4 respectively, matching option (c).