A : tetracyanomethane B : carbondioxide C : benzene D : 1, 3-buta-di-ene. Ratio of \sigma and \pi bo — Chemical Bonding Chemistry Question

💡 Solution & Explanation

Step 1: Calculate the number of σ (sigma) and π (pi) bonds in each molecule to find their ratio (σ / π). Step 2: For A (tetracyanomethane, C(CN)_4): there are 8 σ bonds and 8 π bonds. Ratio = 1. For B (CO_2): there are 2 σ bonds and 2 π bonds. Ratio = 1. For C (benzene, C_6H_6): there are 12 σ bonds and 3 π bonds. Ratio = 4. For D (1,3-butadiene, C_4H_6): there are 9 σ bonds and 2 π bonds. Ratio = 4.5. Step 3: Comparing the ratios: A (1) = B (1) < C (4) < D (4.5). Therefore, the correct order is A = B < C < D, which corresponds to option (a).