What is the increase in volume, when the temperature of 600 ml of air increases from 27°C to 47°C un — States of Matter and Gaseous State Chemistry Question

💡 Solution & Explanation

According to Charles's law (constant pressure): V1 / T1 = V2 / T2. Given: V1 = 600 ml, T1 = 27 + 273 = 300 K, T2 = 47 + 273 = 320 K. V2 = V1 * (T2 / T1) = 600 * (320 / 300) = 640 ml. Increase in volume = V2 - V1 = 640 - 600 = 40 ml.