2 mol of X2(g) contained in a flask of volume 2 L and at 27°C is allowed to react with 2 mol of Y2(g) contained in another flask of volume 6 L and at 27°C, after connecting the two flasks by a narrow

Question

2 mol of X2(g) contained in a flask of volume 2 L and at 27°C is allowed to react with 2 mol of Y2(g) contained in another flask of volume 6 L and at 27°C, after connecting the two flasks by a narrow glass tube, the reaction proceeds as follows:
X2(g) + Y2(g) ⇌ 2XY(g)     (Kc = 16)
The concentration of XY(g) at equilibrium is

Prashant Kotian · Accepted Answer

Correct answer: A.    2 2 X g Y g 2XY g t 0 2 2 2 x 2 x 2x t equi. 8 8 8             2 2 c 2 2 2x / 8 4x K 16 2 x 2 x 8            2x 4 2x 8 4x 2 x       4 x 3    2 4 / 3 1 XY g

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