See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

   2 2 X g Y g 2XY g t 0 2 2 2 x 2 x 2x t equi. 8 8 8             2 2 c 2 2 2x / 8 4x K 16 2 x 2 x 8            2x 4 2x 8 4x 2 x       4 x 3    2 4 / 3 1 XY g