The volume of hydrogen liberated at STP by treating 2.4 g of magnesium with excess of hydrochloric acid is _________ × 10–2 L Given : Molar volume of gas is 22.4 L at STP. Molar mass of magnesium is 2

Question

The volume of hydrogen liberated at STP by treating 2.4 g of magnesium with excess of hydrochloric acid is _________ × 10–2 L Given : Molar volume of gas is 22.4 L at STP. Molar mass of magnesium is 24 g mol–1

Prashant Kotian · Accepted Answer

Correct answer: .. Mg + 2HCl  MgCl2 + H2 1 mole 1 mole 2.4 g of Mg = 0.1 moles 0.1 moles So volume of H2 gas evolved at STP = 0.1  22.4 = 2.24 litre

💡 Solution & Explanation

Practice 22,000+ questions like this