The volume of hydrogen liberated at STP by treating 2.4 g of magnesium with excess of hydrochloric a — JEE Mains Chemistry Past Papers Chemistry Question
Question
The volume of hydrogen liberated at STP by treating 2.4 g of magnesium with excess of hydrochloric acid is _________ × 10–2 L Given : Molar volume of gas is 22.4 L at STP. Molar mass of magnesium is 24 g mol–1
Answer: .
💡 Solution & Explanation
Mg + 2HCl MgCl2 + H2 1 mole 1 mole 2.4 g of Mg = 0.1 moles 0.1 moles So volume of H2 gas evolved at STP = 0.1 22.4 = 2.24 litre
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