Standard enthalpy of vapourisation for CCl4 is 30.5 kJ mol–1. Heat required for vapourisation of 284g of CCl4 at constant temperature is ____kJ. (Given molar mass in g mol–1 ; C = 12, Cl = 35.5)

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Prashant Kotian · Accepted Answer

Correct answer: .. vap H CCl 30.5 kJ / mol   Mass of CCl4 = 284 gm Molar mass of CCl4 = 154 g/mol Moles of CCl4 = 284 154 = 1.844 mol Hvapº for 1 mole = 30.5 kJ/mol Hvapº for 1.844 mol = 30.5 × 1.844 = 56.242 kJ

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