See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Impulse due to ‘N’ would act at the centre of the colliding parts  N 2 x L-x 2       Applying Impulse momentum theorem   0 . (1) N dt M v v      & Applying Angular impulse, angular momentum theorem 2 . (2) 2 12 L x ML N dt            AITS-FT-VIII (Paper-2)-PCM (Sol.)-JEE(Advanced)/18 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 7 Also 0 2 (3) L x v e v           From (1), (2) & (3)   2 2 0 2 1 3 3 2 L x L x v v e L                            0 1 3 for v e x L           For inequality to hold true for all ‘e’   max 1 1 3 3 1 ,