The mole fraction of Schottky defects in a crystal at 1000 K is — Solid State Chemistry Question

💡 Solution & Explanation

The fraction of Schottky defects is: n/N0 = exp(-E / 2RT). Given E = 46,000 cal/mol, R = 2 cal/(mol*K), T = 1000 K. -E / 2RT = -46000 / (2 * 2 * 1000) = -11.5. Since ln(10) = 2.3 => 11.5 = 5 * 2.3 = ln(10^5). Thus, n/N0 = exp(-ln(10^5)) = 10^-5.