The standard entropy change for the reaction is –550 J K at 298 K. [Given: The standard enthalpy change for the reaction s –165 kJ mol ]. The temperature in K at which the reaction attains equilibrium

Question

The standard entropy change for the reaction is –550 J K at 298 K. [Given: The standard enthalpy change for the reaction s –165 kJ mol ]. The temperature in K at which the reaction attains equilibrium is_____. (Nearest Integer) –1 –1

Prashant Kotian · Accepted Answer

Correct answer: 300. **Step 1: Identify the equilibrium condition** At equilibrium, ΔG = 0. Use the Gibbs free energy equation: ΔG = ΔH – TΔS **Step 2: Set up the equation at equilibrium** Since ΔG = 0 at equilibrium: 0 = ΔH – TΔS Therefore: T = ΔH/ΔS **Step 3: Convert enthalpy to consistent units** ΔH = –165 kJ/mol = –165,000 J/mol ΔS = –550 J/(K·mol) **Step 4: Substitute values into the equation** T = ΔH/ΔS = (–165,000 J/mol)/(–550 J/(K·mol)) **Step 5: Calculate temperature** T = 165,000/550 T = 300 K The negative signs cancel out, giving a positive temperature value, which is physically meaningful. Therefore, the answer is 300.

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