See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Balance eq. is   2 2 2 4Au 8CN O 2H O 4Au CN 4OH         (i) 4Au 4Au 4e G 4 96500 1.5 J           J 2 4Au 8CN 4Au CN 4e G 579 729.6 KJ 150.6 KJ            2 4Au 8CN 4Au CN G 2 8 300 38 4 J            (ii) ' 2 2 O 4H 4e 2H O G 4 96500 1.2 J         ' 2 2 3 O 2H O 4e 4OH G 463.2 268.8 kJ 194.4 kJ          ' 2 2 4H O 4H 4OH G 2 8 300 56           ' reaction 3 3 G G G 345 kJ        AITS-CRT-IV (Paper-1)-PCM(Sol.)-JEE(Advanced)/20 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 6