See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

2 2 3 N 3H 2NH   Initial mole 1 3 0 At eq. 1 – x 3 – 3x 2x Out of 4 mole of mixture, 2 mole have reacted and hence 2 mole are left.  1 – x + 3 – 3x = 2 Or 4x = 2 or x = 0.5  Total mole at equilibrium = 1 – x + 3 – 3x + 2x = 4 – 2x = 4 – 2 × 0.5 = 3 No. of mole of NH3 at equilibrium = 2x = 2 × 0.5 = 1 3 NH 1 P p P 3 3      y = 3. AITS-CRT-IV-PCM(Sol.)-JEE(Main)/2021 Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 11 Mathematics PART – C SECTION – A