An optically active alkyl bromide X(C6H13Br) upon treatment with ethanolic KOH solution forms two alkenes Y and Z with their molecular formula (C6H12). Y and Z are positional isomers. Z upon treatment

Question

An optically active alkyl bromide X(C6H13Br) upon treatment with ethanolic KOH solution forms two alkenes Y and Z with their molecular formula (C6H12). Y and Z are positional isomers. Z upon treatment with cold, dilute alkaline KMnO4 solution gives a meso-diol. Hence, X is

Prashant Kotian · Accepted Answer

Correct answer: C. If meso-diol is formed, it means alkenes must be cis-symmetrical-3-hexene. 2 5 3 5 C H OK C C OH   3 bromo hexene X   Br  2 hexene Y    cis 3 hexene Z   Y and Z are position isomer. 4 KMnO Z   C2H5 C2H5 H OH H OH meso by syn addition  For More Material Join: @JEEAdvanced_2024 Rankers Academy JEE AITS-FT-X-PCM(Sol.)-JEE(Main)/2024 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 10

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