As the initial concentration increases from 0.75 to 1.55 M in a reaction, t_1/2 decreases from 60 to — Chemical Kinetics Chemistry Question

💡 Solution & Explanation

Let C1 = 0.75 M, C2 = 1.55 M and t1 = 60 s, t2 = 29 s. Since t_1/2 ∝ C_0^(1-n) => t1/t2 = (C1/C2)^(1-n) => 60/29 ≈ (0.75/1.55)^(1-n) => 2 ≈ (0.5)^(1-n) => 1-n = -1 => n = 2. Thus, the reaction is of second-order.