Correct answer: 8. 3 KE nRT 2   4 4 4 2 2 2 CH CH CH SO SO SO KE n T KE n T    4 800 8 1 400

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AITS & Test SerieshardNUMERICAL

Question

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Answer: 8

💡 Solution & Explanation

3 KE nRT 2   4 4 4 2 2 2 CH CH CH SO SO SO KE n T KE n T    4 800 8 1 400

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