By usual analysis, 1.00g of compound (X) gave 1.79g of magnesium pyrophosphate. The percentage of phosphorus in compound (X) is: (nearest integer) (Given, molar mass in g mol –1: O = 16, Mg = 24, P =

Question

By usual analysis, 1.00g of compound (X) gave 1.79g of magnesium pyrophosphate. The percentage of phosphorus in compound (X) is: (nearest integer) (Given, molar mass in g mol –1: O = 16, Mg = 24, P = 31)

(A) 50
(B) 30
(C) 20
(D) 40

Prashant Kotian · Accepted Answer

Correct answer: A. % of P = 2 2 Mg P O (unknowncompound) n 2 31 w   = 1.79 2 31 100        = 49.99%  50%.

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