See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

    o o o o o o A g 2B g C s D g P 10 min P P 2P P P P 2P P      o 3P 27  o P 9bar  T o P P P 2P P     T o P P 2P   21 9 2P   2P 12  P 6atm  1 60 9 k ln 10 9 6    6 n3   6