Cd(CN)2↓ + 2KCN -> K2[Cd(CN)4] — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

Step 1: Identify starting materials: Cadmium cyanide, Cd(CN)2↓, is an insoluble precipitate. Step 2: Analyze reaction with excess potassium cyanide (KCN): The cyanide ions act as strong ligands and coordinate with Cd2+ to form the highly stable, soluble complex potassium tetracyanocadmate(II), [Cd(CN)4]2-. Step 3: Since the insoluble precipitate dissolves to form a clear solution of a soluble complex, this is classified as a precipitate dissolution reaction (type B).