10 ml. of 2 M NaOH solution is added to 20 ml of 1 M HCl solution kept in a beaker. Now, 10 ml of this mixture is poured into a volumetric flask of 100 mL containing 2 moles of HCI and made the volume

Question

10 ml. of 2 M NaOH solution is added to 20 ml of 1 M HCl solution kept in a beaker. Now, 10 ml of this mixture is poured into a volumetric flask of 100 mL containing 2 moles of HCI and made the volume upto the mark with distilled water. The solution in this flask is:

(A) 10 M HCI solution
(B) 0.2 M NaCI solution
(C) Neutral solution
(D) 20 M HCI solution

Prashant Kotian · Accepted Answer

Correct answer: D. NaOH + HCl  NaCl + H2O Milimole 2×10 1×20 – 0 0 20 milimole Total volume = 30 ml In 10 ml milimole is NaCl = 20 × 10 = 20 Again molarity of HCl = 100 2 × 1000 = 20 M

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