See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

 1 mole 1 mole Ag e Ag s   Only 1 mole Ag can deposit at electrode A. 2 Cu 2e Cu    2 mole Cu will deposit at electrode B. Net mass = mass of Ag at A and mass of Cu at B = 108 + 2 × 63.5 = 235 gm.