See image — Isomerism and Stereochemistry Chemistry Question

💡 Solution & Explanation

Step 1 - Concept: The maximum number of stereoisomers for a molecule is given by 2^n, where n is the total number of stereoelements (chiral centers + geometric double bonds that can exhibit E/Z isomerism). Step 2 - Identify stereoelements in discodermolide: Discodermolide is a well-known natural product. Counting its stereocenters from its established structure: - The delta-lactone ring contributes stereocenters at the carbon bearing OH, the carbon bearing the ring methyl, and the carbon adjacent to the lactone oxygen: approximately 3 stereocenters in the lactone portion. - The chain portion bears multiple OH-bearing and methyl-bearing stereocenters. - Total chiral centers in discodermolide = 13. - Double bonds: there is one internal (trisubstituted) double bond that can exhibit E/Z isomerism = 1 geometric element. The terminal diene (vinyl/diene end) does not contribute E/Z isomerism as it is a terminal alkene. Step 3 - Calculate maximum stereoisomers: Total stereoelements = 13 chiral centers + 1 geometric double bond = 14. Maximum stereoisomers = 2^14. Step 4 - Why other options fail: - 2^15 would require 15 stereoelements, which overcounts. - 2^16 would require 16 stereoelements, which overcounts further. - 2^17 would require 17 stereoelements, which is too large. Step 5 - Conclusion: With 13 stereocenters and 1 E/Z double bond, the maximum number of stereoisomers = 2^13 × 2^1 = 2^14. Therefore, the correct answer is A.