The standard enthalpies of formation of (l), Li+(aq) and OH-(aq) are -285.8, -278.5 and -228.9 kJ/mol, respectively. The standard enthalpy change for the reaction is: 2Li(s) + 2(l) - 2Li+(aq) + 2OH-(

Question

The standard enthalpies of formation of $H_2O$(l), Li+(aq) and OH-(aq) are -285.8, -278.5 and -228.9 kJ/mol, respectively. The standard enthalpy change for the reaction is: 2Li(s) + 2$H_2O$(l) -> 2Li+(aq) + 2OH-(aq) + $H_2$(g)

Prashant Kotian · Accepted Answer

Correct answer: B. For the reaction: 2Li(s) + 2(l) -> 2Li+(aq) + 2OH-(aq) + (g), δ H° = [2 * delta_f H°(Li+, aq) + 2 * delta_f H°(OH-, aq) + 0] - [0 + 2 * delta_f H°(, l)] = [2 * (-278.5) + 2 * (-228.9)] - [2 * (-285.8)] = [-557.0 - 457.8] - [-571.6] = -1014.8 + 571.6 = -443.2 kJ.

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