Spin only magnetic moment in BM of [Fe(CO)4(C2O4)]+ is: [Fe(CO)4(C2O4)]+ ds pqEcdh; vk?kq.kZ dk dsoy — JEE Mains Chemistry Past Papers Chemistry Question
Question
Spin only magnetic moment in BM of [Fe(CO)4(C2O4)]+ is: [Fe(CO)4(C2O4)]+ ds pqEcdh; vk?kq.kZ dk dsoy fLiu eku BM esa gSA (A) 1.73 (B) 0 (C) 1 (D) 5.92
Answer: A
💡 Solution & Explanation
In [Fe(CO)4(C2O4)]+ O.No. of Fe = +3 26Fe+3 = [Ar18] 3d5 4s0 CO is a S.F.L., so paring is present Fe+3 = t2g2,2,1 eg0, 0 number of unpaired electron = 1 so magnetic moment () = ) n ( n B.M. = ) 1 ( = 3 = 1.73 B.M. | JEE MAIN-2021 | DATE : 31-08-2021 (SHIFT-2) | PAPER-1 | OFFICAL PAPER | CHEMISTRY PAGE # 9 Section : Chemistry Section B
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