1cm 1cm B A 10cm Bottom — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

vent front Top In the given TLC, the distance of spot A & B are 5 cm & 7 cm, from the bottom of TLC plate, respectively. Rf value of B is x × 10–1 times more than A. The value of x is_____. Ans. (15) $//(1® Sol. f Distancemovedbysubstance from base line R = Distancemoved by solvent from base line 1cm 1cm  B  A 10cm Bottom Solvent front Top Base line 6cm 4cm 8cm   f A R    f B R      f B f A R 8 R 4   (Rf)B = 1.5 (Rf)A x = 15