See image — GOC and Organic Chemistry Basics Chemistry Question

💡 Solution & Explanation

Step 1: Identify the compound. The structure is H2C=C=CH-CH=O, which is an allenic aldehyde (buta-1,2-dien-1-al or similar). Label the carbons left to right as C1, C2, C3, C4. Step 2: Analyze each carbon's hybridization. C1 (H2C=): This carbon is part of the allene system. In an allene, the two terminal carbons each form one double bond and two single bonds to hydrogens. C1 has bonds to: two H atoms and a double bond to C2. It has 3 groups (2H + C2 via double bond), so it is sp2 hybridized. C2 (=C=): This is the central carbon of the allene (cumulated diene). The central allene carbon forms two double bonds (one to C1, one to C3) with no other substituents. It has only 2 groups (C1 and C3), so it is sp hybridized. C3 (=CH-): This carbon is double-bonded to C2 (part of allene) and single-bonded to C4 and H. It has 3 groups (C2 via double bond, C4, H), so it is sp2 hybridized. C4 (CH=O): This is an aldehyde carbon. It forms a double bond to O and single bonds to C3 and H. It has 3 groups (O via double bond, C3, H), so it is sp2 hybridized. Step 3: Count hybridizations. - sp3: 0 carbons - sp2: C1, C3, C4 = 3 carbons - sp: C2 = 1 carbon Step 4: Match to options. (a) sp3=2, sp2=2, sp=0 — incorrect (b) sp3=1, sp2=3, sp=0 — incorrect (c) sp3=0, sp2=3, sp=1 — matches our analysis (d) sp3=1, sp2=2, sp=1 — incorrect Step 5: Why other options fail. - Option (a) incorrectly assigns sp3 carbons and misses the sp carbon. - Option (b) incorrectly assigns one sp3 carbon and misses the sp carbon. - Option (d) incorrectly assigns one sp3 carbon. Therefore, the correct answer is C.