See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Sol. – – 2 4 2 4 S S CaC O Ca C O    AITS-FT-VIII (Paper-1)-PCM(Sol.)-JEE(Advanced)/20 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 9 2 sp K S S S    sp s K  = (2.5 × 10–9)1/2 = 5 × 10–5 mol litre–1  5 w 5 10 128    w = 6.4 × 10–3g = 6.4 mg