See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

       2 2 3 N g 3H g 2NH g Initial 1 3 0 At equil. 1 x 3 1 x 2x        3 2 4 4 4 2 2NH H SO NH SO    Moles of 2 4 H SO required MV 250 1