100 mL of a sample of hard water requires 25.1 mL of 0.02 N H2SO4 for complete reaction. The hardness of water (density 1 g/mL) is:

Question

Prashant Kotian · Accepted Answer

Correct answer: C. Milliequivalent of H2SO4 = 25.1  0.02 = 0.502 Equivalent = 0.502  10-3 Eq of H2SO4 = Eq of CaCO3  Mass of CaCO3 = Eq  50 = 0.502  10-3  50 = 0.0251 100 mL H2O = 100 g contains 0.0251 g CaCO3 106 g of water will contain 6 2

💡 Solution & Explanation

Practice 22,000+ questions like this