Cis-trans isomerism is exhibited by : — Coordination Compounds Chemistry Question

💡 Solution & Explanation

Step 1: Square planar complexes of the type [MA3B], [MA4], or [MB4] cannot form cis/trans isomers because all adjacent ligand sites are equivalent. Step 2: Square planar complexes of the type [MA2B2] have two distinct geometries: adjacent identical ligands (cis-isomer, 90°) and opposite identical ligands (trans-isomer, 180°). Step 3: Therefore, cis-trans isomerism is exhibited by [PtCl2(NH3)2], which corresponds to option (d).