If an iron (III) complex with the formula – x y Fe NH CN has no electron in its eg orbital, then the value of x + y is (A) 5 (B) 6 (C) 3 (D) 4

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Question

If an iron (III) complex with the formula – x y Fe NH CN has no electron in its eg orbital, then the value of x + y is

(A) 5
(B) 6
(C) 3
(D) 4

Prashant Kotian · Accepted Answer

Correct answer: B. Complex is III 3 2 [Fe(NH ) (CN) ] x = 2 y = 4 so x + y = 6

💡 Solution & Explanation