See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

XL = 50 , XC = 100  Z1 = 100 – 50 I ; Z2 = 100 + 100 i (i 1)   1 2 1 2 Z Z 100 Z (13 i) Z Z 17     100 13 Z 170 ; cos 17 170   2 V P . cos Z   = 629.20 AITS-CRT-II (Paper-2)-PCM (Sol.)-JEE(Advanced)/18 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 9 Chemistry PART – II SECTION – A