Which one of the following is the correct set with respect to molecule, hybridization and shape? — Chemical Bonding Chemistry Question

💡 Solution & Explanation

Step 1: Determine the hybridization and shape of each compound using VSEPR theory. Step 2: BeCl2 has sp hybridization and a linear shape. BCl3 has 3 bond pairs and 0 lone pairs on Boron, resulting in sp2 hybridization and a trigonal (triangular) planar shape. Step 3: Thus, set (c) correctly matches BCl3 with sp2 hybridization and triangular planar shape.