The volume effectively occupied by a single CsCl ion pair in the crystal is — Solid State Chemistry Question

💡 Solution & Explanation

Molar mass of CsCl = 132.5 + 35.5 = 168 g/mol. Mass of 1 CsCl formula unit (ion pair) = 168 / (6 * 10^23) = 2.8 * 10^-22 g. Volume occupied by one formula unit = Mass / Density = (2.8 * 10^-22 g) / 3.5 g/cm3 = 8.0 * 10^-23 cm3 (or ml).