A dye emits 50% of the absorbed energy as fluorescence. If the number of quanta absorbed and emitted — Atomic Structure Chemistry Question
Question
A dye emits 50% of the absorbed energy as fluorescence. If the number of quanta absorbed and emitted is in the ratio 1:2 and it absorbs radiation of wavelength 'x' Angstrom, then the wavelength of the emitted radiation will be
Answer: C
💡 Solution & Explanation
E_emitted = 0.5*E_absorbed => n_e*hc/lambda_e = 0.5*n_a*hc/x. With n_a/n_e = 1/2: 2*n_a/lambda_e = 0.5*n_a/x => lambda_e = 4x.
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