The electronic configuration of four elements are : (I) [Kr] 5s1 (II) [Rn] 5f14 6d1 7s2 (III) [Ar] 3 β Periodic Table and Periodicity Chemistry Question
Question
The electronic configuration of four elements are : (I) [Kr] 5s1 (II) [Rn] 5f14 6d1 7s2 (III) [Ar] 3d10 4s2 4p5 (IV) [Ar] 3d6 4s2. Consider the following statements : (i) I shows variable oxidation state (ii) II is a d-block element (iii) The compound formed between I and III is covalent (iv) IV shows single oxidation state. Which statement is True (T) or False (F)?
π‘ Solution & Explanation
Step 1: Metallic character corresponds to the ease with which an atom loses its valence electrons (electropositivity). Step 2: Going down a group, atomic size increases and the outer electrons are less tightly bound by the nucleus, resulting in lower ionization energy and increased metallic character. Step 3: Moving from left to right across a period, atomic size decreases and effective nuclear charge increases, making it harder to remove valence electrons. Therefore, metallic character decreases across a period.