| JEE MAIN-2022 | DATE : 26-07-2022 (SHIFT-2) | PAPER-1 | | CHEMISTRY PAGE # 3 — JEE Mains Chemistry Past Papers Chemistry Question
Question
| JEE MAIN-2022 | DATE : 26-07-2022 (SHIFT-2) | PAPER-1 | | CHEMISTRY PAGE # 3
Answer: .
💡 Solution & Explanation
As is independent an initial concentration so reaction is 1st order. t = % 100 log k . t = 100 log 693 . 303 . = log . 200 . = 664.65 ×0.7 = 466.66 ≈ 467 sec
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes