25 mL sample of ozonized oxygen at NTP was passed through a solution of KI. The liberated iodine required 15 mL of 0.08 N Na2S2O3 solution for complete titration. Calculate the volume of ozone at NTP

Question

25 mL sample of ozonized oxygen at NTP was passed through a solution of KI. The liberated iodine required 15 mL of 0.08 N Na2S2O3 solution for complete titration. Calculate the volume of ozone at NTP in the given sample.

Prashant Kotian · Accepted Answer

Correct answer: B. Let us assume x mL of O3 in given sample (25 mL) of ozonised oxygen. Now O3 present in the sample reacts with KI to liberate I2 according to following reaction AITS-PT-III-PCM(Sol.)-JEE(Main)/2021 Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 11 3 2 2 2 O 2KI H O O I 2KOH      … (1) The I2 liberated in above reaction [Eq. (1)] further reacts with Na2S2O3 according to the following reaction 2 4 2 3 2 2 6 2

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