For water vap H = 41 kJ mol–1 at 373 K and 1 bar pressure. Assuming that water vapour is an ideal gas that occupies a much larger volume than liquid water, the internal energy changing during evaporat

Question

For water vap H = 41 kJ mol–1 at 373 K and 1 bar pressure. Assuming that water vapour is an ideal gas that occupies a much larger volume than liquid water, the internal energy changing during evaporation of water is ____________ kJ mol–1. [Use : R = 8.3] mol–1 K–1] 373 K ,oa 1 bar nkc ij ty dk vap H = 41 kJ mol–1 gSA ekurs gq, fd ty ok"Ik ,d vkn'kZ xSl gS tks nzo ty dh rqyuk esa dkQh vf/kd vk;ru ?ksjrh gS] ty ds ok"ihdj.k ds nkSjku vkarfjd ÅtkZ ifjorZu gS ____________ kJ mol–1. [iz;ksx djsa : R = 8.3] mol–1 K–1]

Prashant Kotian · Accepted Answer

Correct answer: .. H2O(l) H2O(g) ; Hvap. = 41 kJ/mol H = U + ngRT 41 = U + (1) 1000 . × 373 U = 41 – 3.0959 U = 38 kJ/mol.

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