AgCl↓ + 2KCN -> K[Ag(CN)2] + KCl — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

Step 1: Identify starting materials: AgCl↓ is a white precipitate (insoluble in water). Step 2: Observe the reaction with cyanide (KCN): CN- is a very strong ligand and coordinates with silver to form a highly stable, soluble complex, [Ag(CN)2]-. Step 3: Since the insoluble precipitate AgCl is dissolved to form a clear soluble complex, this is classified as a precipitate dissolution reaction (type B).