See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

2 4 NiCl  sp3 and two unpaired e– – Tetrahedral   2 4 Ni CN  dsp2 and no unpaired e– – Square planar  4 Ni CO sp3 and no unpaired e– – Tetrahedral   2 3 4 Pd NH      dsp2 and no unpaired e–. – Square planar.