If the pKa of lactic acid is 5, then the pH of 0.005 M calcium lactate — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

Ca(Lac)2 Ca2+ + 2 Lac– 5 × 10–3 5 × 10–3 2 × 5 × 10–3 = 10–2 M Calcium lactate is a weak acid and strong base salt so pH = 7 + 2 1 pKa + 2 1 log C = 7 + 2 1 × 5 + 2 1 log 10–2 = 7 + 2.5 – 1 = 6 + 2.5 = 8.5 = 85 × 10–1