Correct answer: 00231.60. Go = o Cell nFE  = -3  96500 (-0.8) = 231600  10–3 = 231.6 kJ mol–1

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AITS & Test SerieshardNUMERICAL

Question

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Answer: 00231.60

💡 Solution & Explanation

Go = o Cell nFE  = -3  96500 (-0.8) = 231600  10–3 = 231.6 kJ mol–1

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