The hybridization of central atoms of compounds A,B,C and D are sp3d, sp3, sp2 and sp respectively. If compounds A and D have same shape like I3^- and compounds B and C have same shape like water mole

Question

The hybridization of central atoms of compounds A,B,C and D are sp3d, sp3, sp2 and sp respectively. If compounds A and D have same shape like I3^- and compounds B and C have same shape like water molecule. Then calculate value of "P + Q + R + S", where P,Q,R and S are number of lone pairs on central atoms of compounds A,B,C and D respectively.

Prashant Kotian · Accepted Answer

Correct answer: 6

**SOLUTION:**
P (SP3D, LINEAR SHAPE LIKE I3^-) = 3 LONE PAIRS.
Q (SP3, BENT SHAPE LIKE H2O) = 2 LONE PAIRS.
R (SP2, BENT SHAPE LIKE H2O) = 1 LONE PAIR.
S (SP, LINEAR SHAPE LIKE I3^-) = 0 LONE PAIRS.
P + Q + R + S = 3 + 2 + 1 + 0 = 6.. Step 1: The stability of an ionic crystal is a measure of the energy required to break the crystal lattice into its constituent gaseous ions. Step 2: This stability is represented directly by the lattice energy of the crystal (the potential energy of the 3D electrostatic lattice). Step 3: Thus, the stability of an ionic crystal principally depends on the lattice energy of the crystal, which corresponds to option (b).

💡 Solution & Explanation

Practice 22,000+ questions like this